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ProgramsBCASemester 1Digital LogicUnit 2: Number System
Chapter Study

BCA Semester 1 – Digital Logic – Unit 2: Number System

Comprehensive questions and detailed answers for Unit 2: Number System. Perfect for exam preparation and concept clarity.

6
Questions
30
Marks
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1

Subtract: 1010.110 - 101.101 using both 2’s and 1’s complement.

MediumTHEORY5 marks2019(TU FOHSS Final)
2

Define positional number system. Calculate following:

a) Subtract 21 from 35 using 2's complement method

b) Convert (62.75)₁₀ into single precision floating point format

MediumTHEORY5 marks2020(TU FOHSS Final)
3

Subtract: 453.35 - 321.17 using both 9's and 10's complement.

MediumTHEORY5 marks2021(TU FOHSS Final)
4

Subtract: 11101.11110100.101 using both 1's and 2's complement.

MediumTHEORY5 marks2022(TU FOHSS Final)
5

Convert +64.35 into IEEE 754 double precision floating point binary number.

MediumTHEORY5 marks2023(TU FOHSS Final)
6

Define Digital computer. Subtract: [101010.101−1000100.001][101010.101−1000100.001][101010.101−1000100.001] using both 1's and 2's complement.

MediumTHEORY5 marks2024(TU FOHSS Final)
Showing 6 questions

Questions in Unit 2: Number System

Subtract: 1010.110 - 101.101 using both 2’s and 1’s complement.

Marks: 5

Year: 2019 Final TU FOHSS

Step 1 – Equalize bit lengths - Minuend = \(1010.1102\) - Subtrahend = \(101.1012\) → add leading zero to integer-part → \(0101.1012\) Thus we compute: 1010.110 – 0101.101 --- Step 2 – 2’s C

Define positional number system. Calculate following: a) Subtract 21 from 35 using 2's complement method b) Convert (62.75)₁₀ into single precision floating point format

Marks: 5

Year: 2020 Final TU FOHSS

1. Definition of Positional Number System A positional number system is a system in which the value of a digit depends on its position in the number as well as the base (radix) of the system. - Exam

Subtract: 453.35 - 321.17 using both 9's and 10's complement.

Marks: 5

Year: 2021 Final TU FOHSS

Step 1: Subtraction Using 9's Complement Step 1.1: Find 9’s complement of the subtrahend (321.17) - For integer part (321): 9’s complement = 999 − 321 = 678 - For fractional part (.17): 9’s compleme

Subtract: 11101.11110100.101 using both 1's and 2's complement.

Marks: 5

Year: 2022 Final TU FOHSS

Subtract: 11101.11110100.101 Step 1: Convert subtraction to addition - Let A = 11101.11110100 - Let B = 101 (assume aligned to same decimal places: 00000.10100000) We want: A − B = A + (−B)

Convert +64.35 into IEEE 754 double precision floating point binary number.

Marks: 5

Year: 2023 Final TU FOHSS

Step 1: Convert integer and fractional part to binary Integer part: 64 64 in binary = 1000000 Fractional part: 0.35 Multiply repeatedly by 2: | Fraction | ×2 | Bit | |----------|----|-----| | 0.35

Define Digital computer. Subtract: \([101010.101−1000100.001]\) using both 1's and 2's complement.

Marks: 5

Year: 2024 Final TU FOHSS

Digital Computer A digital computer is an electronic machine that processes information in binary form (0s and 1s). It performs operations such as input, processing, storage, and output using digita

About Unit 2: Number System Questions

This page contains comprehensive questions from the Unit 2: Number System chapter of Digital Logic, part of the BCA Semester 1 curriculum. All questions include detailed model answers from past TU exam papers.

Study Tips

  • Review concepts before attempting questions
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  • Focus on questions from recent years
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Unit 2: Number System chapter questions with answers for Digital Logic (BCA Semester 1). Prepare for TU exams with our comprehensive question bank and model answers.

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