Evaluate: \[ \quad \text{a) } \int0^2 \frac{dx}{x^2-25} \] \[ \quad \text{b) } \int \frac{2x+5}{x^2+5x} \, dx \]
Marks: 5
Year: 2022 Final TU FOHSS
$\textbf{(a) Evaluation of } \displaystyle \int0^2 \frac{dx}{x^2 - 25}$ First, factor the denominator: \[ x^2 - 25 = (x - 5)(x + 5) \] Using partial fractions: \[ \frac{1}{(x - 5)(x + 5)} = \frac{1}{1